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+Detailed design: Transient Buffer function (LIFT)
+
+
+1) DDR4 memory per receiver input
+
+Bottom up:
+
+Per FPGA there are S_pn = 12 receiver inputs.
+Per FPGA there are N_ddr = 2 DDR4 modules of V_ddr = 8 GByte each.
+==> Per recveiver input N_ddr * V_ddr / S_pn = 1.33 GByte.
+The receiver input data rate is f_adc = 200 MHz and sample width is W_adc = 14 b.
+Assume the samples are stored in 16 b (= 2 bytes), this creates 16/14 = 14 % storage overhead
+Assume 4 % storage overhead for packet header information
+==> Per recveiver input T_tbuf = 1.33 GByte / (2 byte/sample) / 1.04 / f_adc = 3.2 sec maximum storage time.
+==> 192 * 1.33 = 256 GByte / LB for T_tbuf = 3.2 s
+
+Hoe streng is de 3.33 s, mag 3.2 s ook ?
+Moeten we nog grotere 16 GByte modules gaan aanschaffen en te testen met unb2c, zodat we 2x zoveel storage tijd hebben ?
+